Помогите решить систему {x^3-y^3=37 {x-y=1

[latex] \left \{ {{(x-y)( x^{2} +xy+y^2)=37} \atop {x-y=1}} \right. \\ \left \{ {{x^2+xy+y^2=37} \atop {x=y+1}}\right. \\ (y+1)^2+(y+1)y+y^2=37 \\ y^2+2y+1+y^2+y+y^2=37 \\ 3y^2+3y-36=0 \\ y^2+y-12=0 \\ y_{12}= \frac{-1+-7}{2}=-4;3 \\ x_{12}=-3;4 \\ [/latex] зн. решение:(-3;-4);(4;3)