Помогите решить уравнение! 4целых 5/19 + х +1 целая 1/38= 12 целых 1/2

4 5/19 + x +1 1/38 = 12 1/2 81/19 + x + 39/38 = 25/2 162/38 + x + 39/38 - 475/38 = 0 -274/38 + x = 0 x = 274/38 x = 7 8/38 x = 7 4/19

[latex] 4\frac{5}{19} +x+1 \frac{1}{38} =12 \frac{1}{2} \\ \\ 4 \frac{10}{38} +1 \frac{1}{38}+x=12 \frac{19}{38} \\ \\ 5\frac{11}{38}+x= 12 \frac{19}{38} \\ \\ x=12 \frac{19}{38}-5\frac{11}{38} x=7\frac{8}{38}=7 \frac{4}{19}[/latex]