Помогите решить[latex]1- sinx+cosx=0[/latex]

cosx - sinx + 1 = 0 cos(2*x/2) = cos^2(x/2) - sin^2(x/2) sin(2*x/2) = 2sin(x/2)*cos(x/2) 1 = cos^2(x/2) + sin^2(x/2) cos^2(x/2) - sin^2(x/2) - 2sin(x/2)*cos(x/2) + cos^2(x/2) + sin^2(x/2) = 0 2cos^2(x/2) - 2sin(x/2)*cos(x/2) = 0 2cos(x/2)*(cos(x/2) - sin(x/2)) = 0 1) cos(x/2) = 0 x/2 = π/2 + πk x = π + 2πk 2) cos(x/2) - sin(x/2) = 0 sin(x/2) = cos(x/2) tg(x/2) = 1 x/2 = π/4 + πk x = π/2 + 2πk