Помогите с алгеброй [latex] \frac{2a+8}{ a^{3} -8} + \frac{a+2}{ a^{2}+2a+ 4 } [/latex]

[latex]\frac{2a+8}{ a^{3} -8} + \frac{a+2}{ a^{2}+2a+4 }=\frac{2a+8}{ (a-2)(a^2+2a+4)} + \frac{a+2}{ a^{2}+2a+4 }= \\ =\frac{2a+8}{ (a-2)(a^2+2a+4)} + \frac{(a+2) (a-2)}{ (a-2)(a^{2}+2a+4) }=\frac{2a+8+(a+2) (a-2)}{ (a-2)(a^{2}+2a+4) }= \\ =\frac{2a+8+a^2-4}{ (a-2)(a^{2}+2a+4) }=\frac{a^2+2a+4}{ (a-2)(a^{2}+2a+4) }=\frac{1}{ a-2}[/latex]