ПОМОГИТЕ! СРОЧНО! Решите неравенство: [latex]cos \sqrt{4- x^{2} } \ \textless \ 0[/latex]

[latex]cos \sqrt{4-x^2}\ \textless \ 0 \\ \left \{ {{\frac{ \pi }{2} +2 \pi n\ \textless \ \sqrt{4-x^2}\ \textless \ \frac{3\pi }{2} +2 \pi n, nEZ} \atop { 0\leq\sqrt{4-x^2}\leq 2}} \right. \\ \frac{ \pi }{2}\ \textless \ \sqrt{4-x^2}\leq 2\\ \frac{ \pi^2 }{4}\ \textless \ 4-x^2\leq 4 \\ \frac{ \pi^2 }{4}-4\ \textless \ -x^2\leq 0\\ 0\leq x^2\ \textless \ 4- \frac{ \pi^2 }{4} \\ |x|\ \textless \ \frac{ \sqrt{16- \pi ^2} }{2} [/latex]