Помогите срочно √x= -x+2

[latex] \sqrt{x} =-x+2[/latex] [latex] \left \{ {{-x+2 \geq 0} \atop {( \sqrt{x} )^2=(-x+2)^2}} \right. [/latex] [latex] \left \{ {{-x \geq-2} \atop {x=4-4x+x^2}} \right. [/latex] [latex] \left \{ {{x \leq 2} \atop {x^2-5x+4=0}} \right. [/latex] [latex] x^{2} -5x+4=0[/latex] [latex]D=(-5)^2-4*1*4=9[/latex] [latex]x_1= \frac{5+3}{2} =4[/latex] - ∅ [latex]x_2= \frac{5-3}{2}=1 [/latex] Ответ: 1