Помогитеееее срочно!!!

1) [latex]3log_{x} \frac{1}{18}+log_{18} \frac{1}{x}=4 \\ \\ x\ \textgreater \ 0 \\ x \neq 1 [/latex] [latex]-3log_{x}18-log_{18}x=4 \\ -3* \frac{1}{log_{18}x}-log_{18}x -4=0 \\ \\ y=log_{18}x \\ \\ -\frac{3}{y}-y-4=0 [/latex] [latex]y \neq 0 \\ -3-y^2-4y=0 \\ y^2+4y+3=0 \\ D=16-12=4 \\ y_{1}= \frac{-4-2}{2} =-3 \\ y_{2}= \frac{-4+2}{2}=-1 [/latex] При у=-3 [latex]log_{18}x=-3 \\ x=18^{-3} \\ x= \frac{1}{18^3} [/latex] При у=-1 [latex]log_{18}x=-1 \\ x=18^{-1} \\ x= \frac{1}{18} [/latex] Ответ: [latex] \frac{1}{18^3} [/latex];  [latex] \frac{1}{18} [/latex]. 4. [latex]log_{ \frac{1}{2} }(2x-5)=-2[/latex] 2x-5>0 2x>5 x>2.5 [latex]2x-5=( \frac{1}{2} )^{-2} \\ 2x-5=(2^{-1})^{-2} \\ 2x-5=2^2 \\ 2x=4+5 \\ 2x=9 \\ x=4.5[/latex] Ответ: 4,5 5. [latex]log^2_{4}x+log_{4}x-6=0 \\ \\ x\ \textgreater \ 0[/latex] [latex]y=log_{4}x \\ \\ y^2+y-6=0 \\ D=1+24=25 \\ y_{1}= \frac{-1-5}{2}=-3 \\ y_{2}= \frac{-1+5}{2}=2 [/latex] При у=-3 [latex]log_{4}x=-3 \\ x=4^{-3} \\ x= \frac{1}{64} [/latex] При у=2 [latex]log_{4}x=2 \\ x=4^2 \\ x=16[/latex] Ответ: [latex] \frac{1}{64} [/latex];  16 2. [latex]log_{2}(xlog_{2^6}x^3*log_{x} \sqrt{ \sqrt[4]{2} } )=18 \\ \\ x\ \textgreater \ 0 \\ x \neq 1[/latex] [latex]x* \frac{3}{6}log_{2}x*log_{x} \sqrt{2^{ \frac{1}{4} }}=2^{18} \\ \\ x* \frac{1}{2}log_{2}x*log_{x}2^{ \frac{1}{8} }=2^{18} \\ \\ x* \frac{1}{2}* \frac{1}{8}*log_{2}x*log_{x}2=2^{18} [/latex] [latex] \frac{1}{16}x*log_{x}x*log_{2}2=2^{18} \\ x=2^{18}*16 \\ x=2^{18}*2^{4} \\ x=2^{22} [/latex] Ответ: 2²². 3. [latex]log_{ \frac{1}{19} }( \frac{3x}{22}-1 )*log_{ \sqrt[22]{3} }x^{ \frac{1}{22} }=2log_{ \frac{1}{19} }( \frac{3x}{22}-1 ) \\ \\ \frac{3x}{22}-1\ \textgreater \ 0 \\ \\ \frac{3x}{22}\ \textgreater \ 1 \\ \\ 3x\ \textgreater \ 22 \\ x\ \textgreater \ \frac{22}{3} \\ \\ x\ \textgreater \ 7 \frac{1}{3} [/latex] [latex]log_{ \frac{1}{19} }( \frac{3x}{22}-1)*log_{3^{ \frac{1}{22} }}x^{ \frac{1}{22} }-2log_{ \frac{1}{19} }( \frac{3x}{22}-1 )=0 \\ \\ -log \frac{1}{19}( \frac{3x}{22}-1 )*log_{3}x=0 \\ \\ log_{19}( \frac{3x}{22}-1 )*log_{3}x=0 [/latex] 1) [latex]log_{19}( \frac{3x}{22}-1 )=0 \\ \\ \frac{3x}{22}-1=19^0 \\ \frac{3x}{22}=1+1 \\ 3x=2*22 \\ 3x=44 \\ x= \frac{44}{3} \\ x=14 \frac{2}{3} [/latex] 2) [latex]log_{3}x=0 \\ x=3^0 \\ x=1[/latex] не подходит Ответ: 14 ²/₃