Пожалуйста, срочно, решите уравнения, даю 50 баллов

1) [latex] \frac{x-4}{x+1} - \frac{10}{x^2-1} = \frac{3}{8} [/latex] [latex] \frac{x-4}{x+1} - \frac{10}{(x-1)(x+1)} = \frac{3}{8} [/latex] [latex] \frac{(x-4)(x-1)-10}{(x+1)(x-1)} = \frac{3}{8} [/latex] [latex] \frac{ x^{2} -4x-x+4-10}{(x+1)(x-1)} = \frac{3}{8} [/latex] [latex] \frac{ x^{2} -5x-6}{(x+1)(x-1)} = \frac{3}{8} [/latex] ОДЗ: [latex]x \neq 1,[/latex]  [latex]x \neq -1[/latex] [latex]{8( x^{2} -5x-6)=3(x+1)(x-1)} [/latex] [latex]{8 x^{2} -40x-48=3(x^2-1)[/latex] [latex]{8 x^{2} -40x-48-3x^2+3=0[/latex] [latex]5 x^{2} -40x-45=0[/latex] [latex]x^{2} -8x-9=0[/latex] [latex]D=(-8)^2-4*1*(-9)=100[/latex] [latex]x_1= \frac{8+10}{2} =9[/latex] [latex]x_2= \frac{8-10}{2} =-1[/latex] ∅ Ответ: 9 2) [latex] \frac{x+1}{x-3} - \frac{9}{x+3} = \frac{24}{x^2-9} [/latex] [latex] \frac{(x+1)(x+3)-9(x-3)}{(x-3)(x+3)} = \frac{24}{(x-3)(x+3)} [/latex] [latex] \frac{x^2+3x+x+3-9x+27}{(x-3)(x+3)} = \frac{24}{(x-3)(x+3)} [/latex] [latex] \frac{x^2-5x+30}{(x-3)(x+3)} = \frac{24}{(x-3)(x+3)} [/latex] ОДЗ: [latex]x \neq 3,[/latex]   [latex]x \neq -3[/latex] [latex]x^2-5x+30 ={24[/latex] [latex]x^2-5x+30 -24=0[/latex] [latex]x^2-5x+6=0[/latex] [latex]D=(-5)^2-4*1*6=1[/latex] [latex]x_1= \frac{5+1}{2}=3 [/latex]  ∅ [latex]x_2= \frac{5-1}{2}=2[/latex] Ответ: 2 3) [latex] \frac{x-3}{x+5} - \frac{x-9}{x-1} = \frac{48}{(x+5)(x-1)} [/latex] ОДЗ: [latex]x \neq 1,[/latex]  [latex]x \neq -5[/latex] [latex] \frac{(x-3)(x-1)-(x-9)(x+5)}{(x+5)(x-1)} = \frac{48}{(x+5)(x-1)} [/latex] [latex] \frac{x^2-3x-x+3-x^2-5x+9x+45}{(x+5)(x-1)} = \frac{48}{(x+5)(x-1)} [/latex] [latex] \frac{48}{(x+5)(x-1)} = \frac{48}{(x+5)(x-1)} [/latex] [latex]48=48[/latex] Ответ: [latex]x-[/latex] любое число, кроме [latex]x =-5,[/latex] [latex]x=1[/latex]