Ребята, надо найти массовую долю CrN(O3)3, BaCO3, Ag2CO3, MgIO3,NaPO3 (20 баллов ) heeeeeelp

Cr(NO3)3 M(Cr(NO3)3)=52+(14+16*3)*3=238g/mol W(Cr)=52/238*100%=21.85% W(N)=14*3/238*100%=17.65% W(O)=16*9/238*100%=60.5% BaCO3 M(BaCO3)=137+12+16*3=197g/mol W(Ba)=137/197*100%=69.54% W(C)=12/197*100%=6.09% W(O)=16*3/197*100%=24.37% Ag2CO3 M(Ag2CO3)=108*2+12+16*3=276g/mol W(Ag)=108*2/276*100%=76.26% W(C)=12/276*100%=4.35% W(O)=16*3/276*100%=17.39% MgIO3 M(MgIO3)=24+127+16*3=199g/mol W(Mg)=24/199*100%=12.06% W(I)=127/199*100%=63.82% W(O)=16*3/199*100%=24.12% NaPO3 M(NaPO3)=23+31+16*3=102g/mol W(Na)=23/102*100%=22.55% W(P)=31/102*100%=30.39% W(O)=16*3/102*100%=47.06%