Реши уравнение 3ц 1\6 - (х +1 ц 1\ 12) = 1\4 Ц- целых

[latex]3 \frac{1}{6} - (x + 1 \frac{1}{12}) = \frac{1}{4}[/latex] [latex]3 \frac{1}{6} - x - 1 \frac{1}{12} = \frac{1}{4}[/latex] [latex]- x = \frac{1}{4} - 3 \frac{1}{6} + 1 \frac{1}{12} [/latex] [latex]- x = \frac{3}{12} - 3 \frac{2}{12} + 1 \frac{1}{12}[/latex] [latex]- x = -1 \frac{5}{6} [/latex] [latex]x = 1 \frac{5}{6} [/latex]