Решить неравенство log 1/3 (2x+3) меньше log 1/3 ( х-1)

[latex] log_{ \frac{1}{3} } (2x+3)\ \textless \ log_{ \frac{1}{3} } (x-1) [/latex] ОДЗ: [latex] \left \{ {{2x+3\ \textgreater \ 0} \atop {x-1\ \textgreater \ 0}} \right. , \left \{ {{x\ \textgreater \ -1,5} \atop {x\ \textgreater \ 1}} \right. [/latex] x∈(1;∞) основание логарифма а=1/3, знак неравенства меняем: 2x+3>x-1, x>-4 [latex] \left \{ {{x\ \textgreater \ 1} \atop {x\ \textgreater \ -4}} \right. [/latex] x>1 x∈(1;∞)