Решить по формуле Кремера {5x-3y=16 {2x+4y=22{3x+3y=-2{5x-2y=1

1. Находим определитель системы: [latex]\Delta=\left[\begin{array}{ccc}5&-3\\2&4\\\end{array}\right] =20-(-6)=26[/latex] [latex]\Delta_x= \left[\begin{array}{ccc}16&-3\\22&4\\\end{array}\right] =64-(-66)=64+66=130[/latex] [latex]x= \frac{\Delta_x}{\Delta} =130/26=5[/latex] [latex]\Delta_y= \left[\begin{array}{ccc}5&16\\2&22\\\end{array}\right]=110-32=78[/latex] [latex]y= \frac{\Delta_y}{\Delta} =78/26=3[/latex] 2. [latex]\Delta= \left[\begin{array}{ccc}3&3\\5&-2\\\end{array}\right] =-6-15=-21[/latex] [latex]\Delta_x=\left[\begin{array}{ccc}-2&3\\1&-2\\\end{array}\right]=4-3=1[/latex] [latex]x=- \frac{1}{21} [/latex] [latex]\Delta_y=\left[\begin{array}{ccc}3&-2\\5&1\\\end{array}\right]=3+10=13[/latex] [latex]y=- \frac{13}{21} [/latex]