Решить пример для 11 класса

[latex] \sqrt{2} *sin(2\pi*50* \frac{1}{1200}+ \frac{\pi}{12} )= \sqrt{2} *sin(\frac{2\pi*50}{1200}+ \frac{\pi}{12} )=[/latex] [latex]= \sqrt{2} *sin(\frac{100*\pi}{100*12}+ \frac{\pi}{12} ) = \sqrt{2} *sin(\frac{\pi}{12}+ \frac{\pi}{12} ) = \sqrt{2} *sin(\frac{\pi+\pi}{12})=[/latex] [latex]= \sqrt{2} *sin(\frac{2*\pi}{2*6}) = \sqrt{2} *sin(\frac{\pi}{6})= \sqrt{2}*sin( \frac{180^0}{6} ) = \sqrt{2}*sin(30^0)= [/latex] [latex]= \sqrt{2}* \frac{1}{2}= \frac{ \sqrt{2} }{2}[/latex]