Решить систему уравнений: [latex] \left \{ {{x-5y=2} \atop {x^2-y=10}} \right. [/latex]

x-5y=2 x²-y=10 x=2+5y (2+5y)²-y=10 x=2+5y 4+20y+25y²-y-10=0 x=2+5y 25y²+19y-6=0 25y²+19y-6=0 D=19²-4*(-6)*25=361+600=961=31² [latex]y_{1}= \frac{-19- \sqrt{961} }{2*25} = \frac{-19-31 }{50} = \frac{-50}{50} =-1 \\ y_{2}= \frac{-19+\sqrt{961} }{2*25} = \frac{-19+31 }{50} = \frac{12}{50} =0.24[/latex] x=2+5y y₁ = -1 y₂=0.24 x₁=2-5 x₂=2+1,2 y₁ = -1 y₂=0.24 x₁= -3 x₂=3,2 y₁ = -1 y₂=0.24