Решить уравнение a) -20*(x-13)=-220 b) (30-7x)*8=352 c) (2,8-0,1x)*3,7=7,4 d) 5/12y-3/4=1/2

а)-20*(х-13)=-220 -20х+260=-220 -20х=-260-220 -20х=-480 20х=480 х=480:20 х=24 б)(30-7х)*8=352 30-7х=352:8 30-7х=44 -7х=44-30 -7х=14 -х=14:7 х=-2 с)(2,8-0,1х)*3,7=7,4 2,8-0,1х=7,4:3,7 2,8-0,1х=2 -0,1х=2-2,8 -0,1х=-0,8 0,1х=0,8 х=0,8:0,1 х=8 d)5/12у-3/4=1/2 5/12у=1/2+3/4 5/12у=2/4+3/4 5/12у=5/4 у=5/4:5/12 у=5/4*12/5 у=3

[latex]1)-20*(x-13)=-220\\x-13= \frac{-220}{-20} \\x-13=11\\x=11+13\\x=24 \\ \\ 2)(30-7x)*8=352\\30-7x=352/8\\30-7x=44\\7x=30-44\\7x=-14\\x=-2\\\\[/latex] [latex]3)(2.8-0.1x)*3.7=7.4\\2.8-0.1x=7.4/3.7\\2.8-0.1x=2/*10\\28-x=20\\x=28-20\\x=8\\\\[/latex] [latex]4) \frac{5}{12} y- \frac{1}{4} = \frac{1}{2} \\ \frac{5}{12} y= \frac{1}{2} + \frac{1}{4} \\ \\ \frac{5}{12} y= \frac{2+1}{4} \\ \\ \frac{5}{12}y = \frac{3}{4} \\y= \frac{3}{4} : \frac{5}{12} \\ \\y= \frac{5*12}{4*5} \\ \\ y=3[/latex]