Решить уравнение х^2+5х-36=0

[latex] x^{2} [/latex] + 5х-36 = 0 [latex] x^{2} [/latex] → a 5 → b -36 → c D = [latex] b^{2} [/latex] - 4ac = 25-4*(-36) = 169 169 = [latex] 13^{2} [/latex] [latex] x_{1,2} [/latex] = [latex] \frac{-b +(-) \sqrt{D} }{2a} [/latex] [latex] x_{1} [/latex] = [latex] \frac{-5-13}{2} [/latex] = [latex] \frac{-18}{2} [/latex] = -9 [latex] x_{2} [/latex] = [latex] \frac{-5+13}{2} [/latex] = [latex] \frac{8}{2} [/latex] = 4 Ответ: -9; 4. Удачи)