Решите 6.sin2x/tgx=cosx 7.1-cosx+sinx/cosx=0 2sinx-√3/2cosx+1=0 п.с это числитель и знаменатель

6 2sinxcosx:sinx/cosx=cosx 2cos²x-cosx=0 cosx(2cosx-1)=0 cosx=0⇒x=π/2+πn,n∈z cosx=1/2⇒x=+-π/3+2πk,k∈z 7 1-сosx+sinx=0 sin²x/2+cos²x/2-cos²x/2+sin²x/2+2sinx/2cosx/2=0 2sin²x/2+2sinx/2cosx/2=0 2sinx/2(sinx/2+cosx/2)=0 sinx/2=0⇒x/2=πn⇒x=2πn,n∈z sinx/2+cosx/2=0/cosx/2 tgx/2+1=0 tgx/2=-1⇒x/2=-π/4+πk⇒x=-π/2+2πk.k∈z cosx≠0⇒x≠π/2+πm,m∈z x=2πn,n≠(1+2m)/4,n∈z U m∈z x=-π/2+2πk.k≠(1+m)/2,k∈z U m∈z 8 (2sinx-√3)/(2cosx+1)=0 sinx=√3/2⇒x=π/3+2πn,n∈z U x=2π/3+2πk,k∈z cosx≠-1/2⇒x≠+-2π/3+2πm,m∈z x=π/3+2πn,n∈z