Решите неравенства 3х(х+2)-(4-х )(4+х) больше или равно 5(х^2+1)-4(1,5х-1)

[latex]3x(x+2)-(4-x )(4+x) \geq 5(x^2+1)-4(1.5x-1)[/latex] [latex]3x^2+6x-(16-x^2) \geq 5x^2+5-6x+4[/latex] [latex]3x^2+6x-16+x^2 \geq 5x^2-6x+9[/latex] [latex]4x^2+6x-16 - 5x^2+6x-9 \geq 0[/latex] [latex]- x^2+12x-25 \geq 0[/latex] [latex]x^2-12x+25 \leq 0[/latex] [latex]x^2-12x+25=0[/latex] [latex]D=(-12)^2-4*1*25=144-100=44[/latex] [latex]x_1= \frac{12+2 \sqrt{11} }{2} =6+ \sqrt{11} [/latex] [latex]x_2= \frac{12-2 \sqrt{11} }{2} =6-\sqrt{11} [/latex] ----+----[6-√11]----- - -------[6+√11]-----+-----                     /////////////////// Ответ: [latex][6- \sqrt{11} ; 6+ \sqrt{11} ][/latex]