Решите неравенствоlog3(x2+7x-5) больше 1

[latex]log_3(x^2+7x-5)>1[/latex] [latex]x^2+7x-5>3[/latex] [latex]x^2+7x-8>0[/latex] [latex]D=49+32=81; \sqrt{D}=9 [/latex] [latex]x_{1/2}= \frac{-7 \pm9}{2}=1; -8 [/latex] Ответ: [latex]x\in(-\infty; -8) (1;+ \infty)[/latex] ОДЗ: [latex]x^2+7x-5>0[/latex] [latex]D=49+20=69; \sqrt{D}= \sqrt{69} \approx8,3 [/latex] [latex]x_{1/2} \frac{-7\pm8.3}{2} \approx0.65; -7,65[/latex]