Решите пожалуйста. a)(a-b)^2/(b-a)^2 б)12a^3b^5(p-q)^2/36a^2b(q-p)^2 в)16(x-y)^2/48(y-x)^2 г)49xy(c-d)^2/7x^2(d-c)^2

[latex] \frac{(a-b)^2}{(b-a)^2} = \frac{a^2-2ab+b^2}{b^2-2ab+a^2}=1\\\\ \frac{12a^3b^5(p-q)^2}{36a^2b(q-p)^2} = \frac{ab^4(p^2-2qp+p^2)}{3(q^2-2qp+p^2)} = \frac{ab^4}{3}\\\\ \frac{16(x-y)^2}{48(y-x)^2}= \frac{x^2-2xy+y^2}{3(y^2-2xy+x^2)}=1/3\\\\ \frac{49xy(c-d)^2}{7x^2(d-c)^2}= \frac{7y}{x} [/latex]