Решите: sin6x * cos6x = -1/2; sinx + sin3x = 0; sin3x - sin7x = 0.

1)sin6x*cos6x=-1/2|*2 2sin6xcos6x=-1 sin12x=-1 12x=-п/2+2пn,n€z x=-п/24+пn/6,n€z 2)sinx+sin3x=0 2sin(x+3x/2)cos(x-3x/2)=0 2sin2xcosx=0|:2 sin2xcosx=0 sin2x=0 2x=пn,n€z x=пn/2,n€z cosx=0 x=п/2+пn,n€z 3)sin3x-sin7x=0 2sin(3x-7x/2)cos(3x+7x/2)=0 -2sin2xcos5x=0 |:(-2) sin2xcos5x=0 sin2x=0 2x=пn,n€z x=пn/2,n€z cos5x=0 5x=п/2+пn,n€z x=п/10+пn/5,n€z