Решите систему уравнений (2-x)/3-(y+6)/6=0 x+2y=-1

[latex] \left \{ {{\frac{2-x}{3}-\frac{y+6}{6}=0} \atop {x+2y=-1}} \right. \\ \left \{ {{\frac{4-2x-y-6}{6}=0} \atop {x+2y=-1}} \right. \\ \left \{ {{-2x-y-2=0} \atop {x+2y=-1}} \right. \\ \left \{ {{-2x-y=2} \atop {x+2y=-1}} \right. \ \ \ \ (*2)\\ \left \{ {{-4x-2y=4} \atop {x+2y=-1}} \right. \ \ \ \ (+)\\ -3x=3\\ x=-1\\ -1+2y=-1 => y=0[/latex] Ответ: х=-1; у=0