Решите систему уравнений 5х^2 + y^2=36 10x^2 + 2y^2=36x

[latex] \left \{ {5x^2+y^2=36} \atop {10x^2+2y^2=36x}} \right. \\ \left \{ {5x^2+y^2=36}} \atop {5x^2+y^2=18x}} \right. \\ 18x=36 \\ x=2 \\ 20+y^2=36 \\ y^2=16 \\ y_1=4 \\ y_2=-4[/latex] Ответ: [latex](x_1;y_1)=(2;4), (x_2;y_2)=(2;-4)[/latex]

5х²+у²=36 (1) 10х²+2у²=36х (2) 5х²+у²=36 (1) 5х²+у²=18х (2) (делили на 2) 36=18х х=2 у=4 у=-4