Решите систему уравнений и найти ОДЗ log2(x-y)=3 ; 4^log2(корень x+y)=10

[latex] \left \{ {{log_2(x-y)=3} \atop {4^{log_2\sqrt{x+y}}=10}} \right. [/latex] ОДЗ:[latex]x-y\ \textgreater \ 0;x\ \textgreater \ y[/latex] [latex] \sqrt{x+y}\ \textgreater \ 0;x+y\ \textgreater \ 0;x\ \textgreater \ -y [/latex] [latex] \left \{ {{log_2(x-y)=log_2 8} \atop {2^{2log_2\sqrt{x+y}}=10}} \right. [/latex] [latex] \left \{ {{(x-y)=8} \atop {2^{log_2(x+y)}=10}} \right. [/latex] [latex] \left \{ {{x-y=8} \atop {x+y=10}} \right. [/latex] [latex]\left \{ {{2x=18} \atop {x+y=10}} \right.[/latex] [latex]\left \{ {{x=9} \atop {9+y=10}} \right.[/latex] [latex]\left \{ {{x=9} \atop {y=1}} \right.[/latex]