Решите систему уравнений x^2-y^2=12 x+y/x-y=3

x≠y x+y=3(x-y) x²-y²=12 (x-y)(x+y)=12 3(x-y)²=12 !x-y!=2 1/ x-y=2 x+y=6 2x=8 x=4 y=2 2/ x-y=-2 x+y=-6 2x=-8 x=-4 y=-2 (4 2 )(-4 -2)