Решите уравнение 1/(3+1)+1/(9х2+6х+1)=2

1/(3x+1)+1/(9x^2+6x+1)=2; 1/(3x+1)+1(3x+1)^2=2; (3x+1+1)=2(3x+1)^2; 3x+2=18x^+12x+2; +2-2= 18x^2+9x; 9x(2x+1)=0; 1) 9x=0; x=0; 2) 2x+1=0; 2x=-1; x= -1/2.