Решите уравнение 2cos2x=√3

[latex]2cos2x = \sqrt{3} \\ \\ cos2x = \dfrac{ \sqrt{3}}{2} \\\\ 2x = \pm \dfrac{ \pi }{6} + 2 \pi n, \ n \in Z \\ \\\ \boxed{x = \pm \dfrac{ \pi }{12} + \pi n, \ n \in Z}[/latex]