Решите уравнение [latex] 3^{4x+5}- 2^{4x+7}- 3^{4x+3} - 2^{4x+4}=0 [/latex]

3^(4x+5)-2^(4x+7)-3^(4x+3)-2^(4x+4)=0 3^(4x+5)-3^(4x+3)=2^(4x+7)+2^(4x+4) (3^(4x+3))*(3²-3⁰)=(2^(4x+4))*(2³+2⁰) (3^(4x+3))*(9-1)=(2^(4x+4))*(8+1) (3^(4x+3))*8=(2^(4x+4))*9 |: 72 (3^(4x+3))/9=(2^(4x+4))/8 3^(4x+3-2)=2^(4x+4-3) 3^(4x+1)=2^(4x+1) a^m=b^m, ⇒m=0 4x+1=0, 4x=-1 x=-0,25