Решите уравнение: [latex] \frac{3-x}{3}= \frac{x+1}{2}- \frac{5x}{4} [/latex]

[latex] \frac{3-x}{3} = \frac{x+1}{2} - \frac{5x}{4} \\ \frac{3-x}{3}- \frac{x+1}{2} +\frac{5x}{4} =0 \\ \frac{4(3-x)-6(x+1)+15x}{12} =0 \\ \frac{12-4x-6x-6+15x}{12} =0 \\ 6+5x=0 \\ x= -\frac{6}{5} [/latex]

1-x/3-x/2-1/2+5x/4=0 1/2=x(-5/4+1/3+1/2) 1/2=-5/12x   x=-1/2*12/5=-6/5