Решите уравнение: [latex] \frac{sinx-cosx}{4x- \pi } [/latex]=0

[latex] \left \{ {{sinx-cosx=0} \atop {4x-\pi \neq 0}} \right. x\neq\frac{\pi}{4}\\sinx=cosx|:cosx\neq0(x\neq\frac{\pi}{2}+\pi n, n\in Z)\\tgx=1\\ \left \{ {{x=\frac{\pi}{4}+\pi n} \atop {x\neq \frac{\pi}{4}} \right. , n\in Z\\x=\frac{\pi}{4}+\pi n, n \in z, n=neq 0[/latex]