Решите уравнение x^3-2x^2-9x+18=0

x^2(x-2) -9(x-2) = 0 (x^2 - 9)(x-2) = 0 (x-3)(x+3)(x-2) = 0 x1 = 3 x2 = -3 x3 = 2

[latex]x^{2}(x+2)-9(x+2)=0,[/latex] [latex](x^{2}-9)(x+2)=0,[/latex] [latex](x-3)(x+3)(x+2)=0[/latex] [latex]x=-2[/latex] [latex]x=-3[/latex] [latex]x=3[/latex]