Решите уравнение:х-1 = √(2 х ² - 3х - 5)

[latex]x-1= \sqrt{2x^2-3x-5} [/latex] [latex] \left \{ {{x^2-2x+1=2x^2-3x-5} \atop {x-1 \geq 0}} \right. [/latex] [latex] \left \{ {{x^2-x-6=0} \atop {x \geq 1}} \right. [/latex] [latex] \left \{ {{(x-3)(x+2)=0} \atop {x \geq 1}} \right. [/latex] [latex]x=3[/latex] [latex]x=-2[/latex] - постороний тк [latex]x \geq 1 [/latex]