Решите. (y-2)^2-(y-2)

y²-4y+4-y+2=0 y²-5y+6=0 D=25-4*6 = 1 y1 = (5+1)/2 = 3 y2 = (5-1)/2 = 2

(y-2)²-(y-2)=y²-4y+4-y+2=y²-5y+6