Sin^2x/2 = 3cos^2x/2

sin²x/2=3cos²x/2 l: сos^x tg²x/2=3 1- tgx/2=√3 x/2=π/3+πn x1=2π/3+2πn 2- tgx/2=-√3 x/2=-π/3+πn x2=-2π/3+2πn Ответ-x1=2π/3+2πn , x2=-2π/3+2πn