Сколько будет 72/3+(345+89)×332

[latex] \frac{72}{3} +(345+89)*332= \\ (1) \frac{72}{3} +434*332=144088. \\ (2)\frac{72}{3} +144088= \\(3) \frac{72}{3} +144088= \frac{72}{3} +\frac{144088}{1}= \frac{432264-72}{3}=\frac{432192(3}{3}=144064 \\Good luck[/latex]