Срочно! (1/8x^3+1/16y^2)

= (2y^2+x^3)/(16x^3y^2)  

[latex]( \frac{1}{8} x^3+ \frac{1}{16} y^2)= \frac{x^3}{8} + \frac{y^2}{16} = \boxed{(\frac{x}{2})^3 + (\frac{y}{2} )^4}[/latex]