Срочно! Решите уравнение: (3x+1)^2-x(7x+5)=4

9x^2 + 6x + 1 - 7x^2 - 5x = 4 2x^2 + x - 3 = 0 D = 1^2 - 4*2*(-3) = 1 + 24 = 25 [latex] x_{1} = \frac{-1 - \sqrt{25} }{2*2} = \frac{-1 -5}{4} =- \frac{6}{4} = - \frac{3}{2} [/latex] [latex]x_{2} = \frac{-1 + \sqrt{25} }{2*2} = \frac{-1 + 5}{4} = \frac{4}{4} = 1 [/latex]