Упростите выражение √(a+3-4√(a-1))-√(a+8-6√(a-1)) при a больше 10

[latex] a\ \textgreater \ 10\\\\\sqrt{a+3-4\cdot \sqrt{a-1} } -\sqrt{a+8-6\cdot \sqrt{a-1} }= \\\\=\sqrt{ (a-1)+4-2\cdot 2\cdot \sqrt{a-1} } -\sqrt{(a-1)+9-2\cdot 3\cdot \sqrt{a-1} } =\\\\= \sqrt{(\sqrt{a-1}-2)^2}-\sqrt{(\sqrt{a-1}-3)^2} =\\\\=|\sqrt{a-1}-2|-|\sqrt{a-1}-3|=\\\\\\\star \; \; a\ \textgreater \ 10\; \; \Rightarrow \; \; a-1\ \textgreater \ 9\; \; \Rightarrow \; \; \sqrt{a-1}-2\ \textgreater \ 0\; \; i\; \; \sqrt{a-1}-3\ \textgreater \ 0\; ,\\\\|\sqrt{a-1}-2|=\sqrt{a-1}-2\; \; ;\; \; |\sqrt{a-1}-3|=\sqrt{a-1}-3\; \; \star \\\\\\=\sqrt{a-1}-2-(\sqrt{a-1}-3)=-2+3=1[/latex]