Упростите выражениеа) ([latex] (a^{ \frac{1}{6} } + 1) ( a^{ \frac{1}{6} } -1) ( a^{ \frac{1}{3} } +1) [/latex]б) ([latex] (\frac{ a-b }{ a^{ \frac{1}{2} } - b^{ \frac{1}{2} } } - \frac{ a^{ \frac{3}{2} }- b^{ \frac{3}{2} } }{...

[latex] (a^{ \frac{1}{6} } + 1) ( a^{ \frac{1}{6} } -1) ( a^{ \frac{1}{3} } +1)= (a^{ \frac{1}{3} } -1) ( a^{ \frac{1}{3} } +1)=a^{ \frac{2}{3} } -1[/latex] [latex](\frac{a-b}{a^{\frac{1}{2}}-b^{\frac{1}{2}}}-\frac{a^{\frac{3}{2}}-b^{ \frac{3}{2}}}{a-b})(b^{\frac{1}{2}}+a^{\frac{1}{2}})= (\frac{(a-b)(a^{\frac{1}{2}}+b^{\frac{1}{2}})}{a-b}- \frac{a^{\frac{3}{2}}-b^{\frac{3}{2}}}{a-b})(b^{\frac{1}{2}}+a^{\frac{1}{2}})=[/latex] [latex]=(\frac{a^{\frac{3}{2}}+ab^{\frac{1}{2}}-ba^{\frac{1}{2}}-b^{\frac{3}{2}}-a^{\frac{3}{2}}+b^{\frac{3}{2}}}{a-b})(b^{\frac{1}{2}}+a^{ \frac{1}{2}})= (\frac{a^{\frac{1}{2}}b^{\frac{1}{2}}(a^{\frac{1}{2}}-b^{\frac{1}{2}})}{a-b})(b^{\frac{1}{2}}+a^{ \frac{1}{2}})= \\\ =\frac{a^{\frac{1}{2}}b^{\frac{1}{2}}(a-b)}{a-b}=a^{\frac{1}{2}}b^{\frac{1}{2}[/latex]