Упростить логичесую функцию (x*!y+z)(!x+y)+!z

(x*!y+z)(!x+y)+!z = = x*!y*(!x+y)+z*(!x+y)+!z = = x*!y*!x+x*!y*y+z*(!x+y)+!z = x*!y*!x = 0 x*!y*y = 0 = z*(!x+y)+!z