X^2 = 4+корень из (2x^2-5)

[latex]\\x^2=4+\sqrt{2x^2-5}\\ x^2-4=\sqrt{2x^2-5}\\ 2x^2-5\geq0\wedge x^2-4\geq0\\ 2x^2\geq5\wedge x^2\geq4\\ x^2\geq\frac{5}{2}\wedge x\in(-\infty,-2\rangle\cup\langle,2,\infty)\\ x\in((-\infty,-\sqrt{\frac{5}{2}}\rangle\cup\langle\sqrt{\frac{5}{2}},\infty))\cap((-\infty,-2\rangle\cup\langle,2,\infty))\\ D:x\in(-\infty,-2\rangle\cup\langle,2,\infty)\\\\ (x^2-4)^2=2x^2-5\\ x^4-8x^2+16=2x^2-5\\ x^4-10x^2+21=0\\ x^4-3x^2-7x^2+21=0\\ x^2(x^2-3)-7(x^2-3)=0\\ (x^2-7)(x^2-3)=0\\ [/latex] [latex]\\x=-\sqrt 7 \vee x=\sqrt 7\vee x=-\sqrt 3\vee x=\sqrt 3\\ \{-\sqrt 3,\sqrt 3\}\not \in D\\\\ \underline{x=-\sqrt7 \vee x=\sqrt 7} [/latex]