(x^2-6x)^2+14(x-3)^2=81

[latex](x^2-6x)^2+14(x-3)^2=81\\ (x^2-6x)^2+14(x-3)^2-81=0\\ (x^2-6x)^2+14(x^2-6x+9)-81=0\\ zamena\\ x^2-6x=t\\ t^2+14t+14*9-81=0\\ t^2+14t+45=0\\ (t+5)(t+9)=0\\ t=-5;-9\\\\ x^2-6x=-5\\ x^2-6x+5=0\\ D=36-4*1*5=4^2\\ x_{1}=\frac{6+4}{2}=5\\ x_{2}=\frac{6-4}{2}=1\\\\ x^2-6x+9=0\\ (x-3)^2=0\\ x=3[/latex] Ответ  1;3;5