∫₀¹x^3dx/√(4-x^8)Терміново. Допоможіть

[latex] \int\limits^1_0 {\frac{x^{3}}{ \sqrt{4-x^{8}} }} \, dx = \int\limits^1_0 {\frac{1}{ \sqrt{4-x^{8}} }} \, d(x^{4} ), x^{4}=t, x^{8}=t^{2}, \int\limits^1_0 {\frac{1}{ 4\sqrt{4-t^{2}} }} \, dt=\frac{1}{4}arcsin(\frac{t}{2}) [/latex] [latex]arcsin(\frac{t}{2})=arcsin(\frac{x^{4}}{2}) \\[/latex] [latex]F(a)-F(b)=\frac{1}{4}arcsin(\frac{1}{2})-\frac{1}{4}arcsin(\frac{0}{2})=\frac{ \pi }{24}[/latex]