1)СosA=1/3 SinA=? 2)CosA=24/25 TgA-?

[latex]\cos a = \frac13\\ \sin a = 1 - \cos^2a=1-\frac19=\frac89\\ \\ \cos a=\frac{24}{25}\\ \tan a = \frac{\sin a}{\cos a}=\frac{1- \cos ^2 a}{\cos^2a}=\frac{1-\frac{576}{625}}{\frac{576}{625}}=\frac{49}{576}[/latex]