2x/x^2-1=x/x+1+x/x-1

[latex]x\neqб1\\\frac{2x}{x^2-1}=\frac{x}{x+1}+\frac{x}{x-1}=\frac{x(x-1)}{(x+1)(x-1)}+\frac{x(x+1)}{(x-1)(x+1)}=\frac{x(x-1)+x(x+1)}{x^2-1}\\\\2x=x(x-1+x+1)\\2x=2x^2\\x-x^2=0\\x(x-1)=0\\x=0[/latex]