(a+3)^2        a^2-4 -----------  *   ---------- 2a-4              3a+9

[latex] \frac{(a + 3)^2}{2a - 4} * \frac{a^2 - 4}{3a + 9} = \frac{(a + 3)^2}{2 (a - 2)} * \frac{(a - 2)(a + 2)}{3 (a + 3)} = \frac{(a + 3)(a + 2)}{6} = \frac{a^2 + 5a + 6}{6} [/latex]