Найдите корни уравнения х+2/х==51/7

[latex]x+ \frac{2}{x} =- \frac{51}{7} \\ \frac{ x^{2} +2}{x} =- \frac{51}{7} \\ 7 x^{2} +14=-51x \\ 7 x^{2} +51x+14=0 \\ D=2601-392=2209=47^{2}\ \textgreater \ 0 \\ x_{1,2} = \frac{-51+-47}{14} \\ x1=- \frac{4}{14} = - \frac{2}{7} \\ x2= -7 \\ [/latex]