Найти область определения и указать множество значений функции f(x)=0,5arccos(4-5x)-2

y = arccos (x) D(y) = [ - 1; 1] E(y) = [ 0; pi] y = arccos (5x) D(y) = [ - 1/5; 1/5] E(y) = [ 0; pi] y = arccos ( - 5x) D(y) = [ - 1/5; 1/5] E(y) = [ 0; pi] y = arccos (4 - 5x) D(y) = [ 3/5; 1] E(y) = [ 0; pi] y = 0,5*arccos (4 - 5x) D(y) = [ 3/5; 1] E(y) = [ 0; pi/2] y = 0,5*arccos (4 - 5x) - 2 D(y) = [ 3/5; 1] E(y) = [ - 2; pi/2 - 2]