Первое и второе уравнения

1) (4х+1)(16х^2–4х+1)–16х(4х^2–5)=17 64х^3–1–64х^3+80х=17 80х=18 х=9/40 4–х^2 х–х^2 (х–1)^2 7х^2 2) --------- – --------- = ---------- – ------- 3 4 9 36 16–4х^2–3х+3х^2 4(х–1)^2–7х^2 ------------------------- = --------------------- 12 36 –х^2–3х+16 4х^2–8х+4–7х^2 ----------------- = ------------------------- 12 36 –х^2–3х+16 –3х^2–8х+4 ----------------- = ------------------ | •(–36) 12 36 3х^2+9х–48 = 3х^2+8х–4 х = 44