Помогите! 1-sin^2 x/2=0

1-sin²(x/2)=0 (1-sin(x/2))*(1+sin9x/2))=0 1-sin(x/2)=0 или 1+sin(x/2)=0 1. 1-sin(x/2)=0. sin(x/2)=1.   x/2=π/2+2πn, n∈Z |*2 x₁=π+4πn, n∈Z 2. 1+sin(x/2)=0. sin(x/2)=-1.   x/2=-π/2+2πn, n∈Z |*2 x₂=-π+4πn, n∈Z